A unit cell must be electrically neutral. What is the charge on the oxygen ion assuming it has a full valence shell? Based on the ratio of two oxide ions to one Zr cation, what is the charge in the Zr ion?
A unit cell must be electrically neutral. What is the charge on the oxygen ion assuming it has a full valence shell? Based on the ratio of two oxide ions to one Zr cation, what is the charge in the Zr ion?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A unit cell must be electrically neutral.
What is the charge on the oxygen ion assuming it has a full valence shell?
• Based on the ratio of two oxide ions to one Zr cation, what is the charge in the Zr
ion?
In the oxygen sensor, ¼ of the Zr's have been replaced with Ca. (This is called
"doping".)
What is the usual charge on Ca (assuming a full valence shell)?
Calculate the total positive charge from atoms fully in the unit cell.
(% of Zr atoms in unit cell
x charge on Zr + charge on Ca =
To balance the unit cell, you must have (-
on atoms in the unit cell.
What has to happen to the number of oxygen ions to accommodate the
replacement of Zr by Ca? In other words, how many oxide ions will be in the
'doped' cell?
A loss of an oxide atom results in a 'vacancy'. The presence of these vacancies is
required for conductivity in the solid state.
How many vacancies will be in the doped cell?
Explain how these vacancies allow oxide ions to move through the material.
In an oxygen sensor, there is a platinum electrode on either side of the Ca-doped
zirconium oxide. The platinum adsorbs oxygen from the air and converts it into the
oxide ion that migrates though the structure.
How many electrons are needed to convert oxygen into oxide ion?
When oxide ions get to the other side of the material, they are converted back into
oxygen. The electrons flow through the Pt electrode (electrical conductivity), through
a circuit, and back to the other platinum electrode.
Explain why electrons easily flow through the metal of the Pt electrodes. Include
a comment on electronegativity and metallic bonding.
This current creates a potential difference (voltage). The measured potential can be
used to calculate the relative oxygen concentration on each side of the oxygen sensor.
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