What is the change of energy (L. atm) of a system that absorbed 15.2 L.atm of heat and had its volume changed from 3.9 L to 18.1 L against a pressure of 1.5 atm? AE = 15.2 + [1.5(18.1 + 3.9)] AE = -15.2 + [1.5(18.1 - 3.9)] AE = -15.2 + [-1.5(18.1 - 3.9)] AE = 15.2 +[- 1.5(18.1 - 3.9)]
What is the change of energy (L. atm) of a system that absorbed 15.2 L.atm of heat and had its volume changed from 3.9 L to 18.1 L against a pressure of 1.5 atm? AE = 15.2 + [1.5(18.1 + 3.9)] AE = -15.2 + [1.5(18.1 - 3.9)] AE = -15.2 + [-1.5(18.1 - 3.9)] AE = 15.2 +[- 1.5(18.1 - 3.9)]
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![What is the change of energy (L. atm) of a system that absorbed 15.2 L.atm of
heat and had its volume changed from 3.9 L to 18.1 L against a pressure of 1.5
atm?
O AE = 15.2 + [1.5(18.1 + 3.9)]
AE = -15.2 + [1.5(18.1 - 3.9)]
AE = -15.2 + [-1.5(18.1 - 3.9)],
O AE = 15.2 +[- 1.5(18.1 - 3.9)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb196f2c8-5e5b-4365-a25c-60aea5fa5b45%2Ff34e749e-bc56-4033-85e7-421a9e32f3c3%2F03nnq5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:What is the change of energy (L. atm) of a system that absorbed 15.2 L.atm of
heat and had its volume changed from 3.9 L to 18.1 L against a pressure of 1.5
atm?
O AE = 15.2 + [1.5(18.1 + 3.9)]
AE = -15.2 + [1.5(18.1 - 3.9)]
AE = -15.2 + [-1.5(18.1 - 3.9)],
O AE = 15.2 +[- 1.5(18.1 - 3.9)]
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