What is the change in dimension in the 2 direction in mm?  What is the σ1 component of the stresses required to cause these deformations in GPa? What is the σ3 component of the stresses required to cause these deformations in MPa?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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What is the change in dimension in the 2 direction in mm? 

What is the σ1 component of the stresses required to cause these deformations in GPa?
What is the σcomponent of the stresses required to cause these deformations in MPa?
E₁
E2
E3
23
V13
V12
G23
G13
G12
α1
α2
α 3
B₁
В
Graphite-polymer
composite¹
155.0 GPa
12.10 GPa
12.10 GPa
0.458
0.248
0.248
3.20 GPa
4.40 GPa
4.40 GPa
-0.01800 x 10-6°C
24.3 × 10-6°C
24.3 × 10-6°C
146.0 × 10-6/%M
4770 × 10-%%M
4770 x 10-6/%M
A3 = 50 mm
Glass-polymer
composite
A₂ = 50 mm
50.0 GPa
15.20 GPa
15.20 GPa
0.428
0.254
0.254
3.28 GPa
4.70 GPa
4.70 GPa
6.34 x 10-6°C
23.3 x 10-6°C
23.3 x 10-6°C
434 x 10-6/%M
6320 × 10-6/%M
6320 x 10-6/%M
A₁ = 50 mm
¹In the chapters to follow it will be assumed that a layer thickness is 150 × 10-6, m, or
0.150 mm.
2 G=E/2(1 + v).
2
Answer questions 1 through 3 for a 50 mm cube of
graphite-reinforced material that is extended in the 1
direction by 0.90 mm and is constrained against
contraction in the 3 direction. Assume that there is no
constraint in the 2 direction.
1
Aluminum
(a) A 50 mm cube of graphite-epoxy
72.4 GPa
72.4 GPa
72.4 GPa
0.300
0.300
0.300
22.5 x 10-6°C
22.5 x 10-6°C
22.5 x 10-6°C
3
0
0
0
L
2
Transcribed Image Text:E₁ E2 E3 23 V13 V12 G23 G13 G12 α1 α2 α 3 B₁ В Graphite-polymer composite¹ 155.0 GPa 12.10 GPa 12.10 GPa 0.458 0.248 0.248 3.20 GPa 4.40 GPa 4.40 GPa -0.01800 x 10-6°C 24.3 × 10-6°C 24.3 × 10-6°C 146.0 × 10-6/%M 4770 × 10-%%M 4770 x 10-6/%M A3 = 50 mm Glass-polymer composite A₂ = 50 mm 50.0 GPa 15.20 GPa 15.20 GPa 0.428 0.254 0.254 3.28 GPa 4.70 GPa 4.70 GPa 6.34 x 10-6°C 23.3 x 10-6°C 23.3 x 10-6°C 434 x 10-6/%M 6320 × 10-6/%M 6320 x 10-6/%M A₁ = 50 mm ¹In the chapters to follow it will be assumed that a layer thickness is 150 × 10-6, m, or 0.150 mm. 2 G=E/2(1 + v). 2 Answer questions 1 through 3 for a 50 mm cube of graphite-reinforced material that is extended in the 1 direction by 0.90 mm and is constrained against contraction in the 3 direction. Assume that there is no constraint in the 2 direction. 1 Aluminum (a) A 50 mm cube of graphite-epoxy 72.4 GPa 72.4 GPa 72.4 GPa 0.300 0.300 0.300 22.5 x 10-6°C 22.5 x 10-6°C 22.5 x 10-6°C 3 0 0 0 L 2
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