What is the cell potential (EO) for a galvanic cell formed from the following two half-reactions? PbO2(s) + 3 H*(a) + HSO4-(aq) + 2 e-+ PBSO4(s) + 2 E° = 1.690 V %3D H20(1) PbSO4(s) + H*(aq) + 2 e- → Pb(s) + HSO4-(aq) E° = -0.356 V (A) +1.334 V (B) -2.046 V c) +2.046 V D) +2.758 V

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What is the cell potential (EO) for a galvanic cell formed from the following two half-reactions?
PbO2(s) + 3 H*(a) + HSO4-(aq) + 2 e-+ PBSO4(s) + 2
E° = 1.690 V
%3D
H20(1)
PbSO4(s) + H*(aq) + 2 e- → Pb(s) + HSO4-(aq)
E° = -0.356 V
(A) +1.334 V
(B) -2.046 V
c) +2.046 V
D) +2.758 V
Transcribed Image Text:What is the cell potential (EO) for a galvanic cell formed from the following two half-reactions? PbO2(s) + 3 H*(a) + HSO4-(aq) + 2 e-+ PBSO4(s) + 2 E° = 1.690 V %3D H20(1) PbSO4(s) + H*(aq) + 2 e- → Pb(s) + HSO4-(aq) E° = -0.356 V (A) +1.334 V (B) -2.046 V c) +2.046 V D) +2.758 V
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