What is the big-O complexity of the following function in terms of n? def rate(n): i = 0 while i < 10: j = n while j > 0: print(i, j) j -= 2 i += 1 IMPORTANT: There is no "Check" button. You can change your answer as many times as you like. Select one: O a. 0(1) O b. O(n log n) O c. O(n^2) O d. O(log n) O e. O(n^3) O f. O(n)

What is the big-O complexity of the following function in terms of n? def rate(n): i = 0 while i < 10: j = n while j > 0: print(i, j) j -= 2 i += 1 IMPORTANT: There is no "Check" button. You can change your answer as many times as you like. Select one: O a. 0(1) O b. O(n log n) O c. O(n^2) O d. O(log n) O e. O(n^3) O f. O(n)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Which is the base case for the following recursive function? void printOut( int n ) // Print nonnegative n { if( n >= 10 ) printOut( n / 10 ); printDigit( n % 10 ); } Group of answer choices A.if ( n >= 10 ) B.printOut( n/10 ); C.printDigit( n%10 ); D.if ( n >= 10) E.None of the above
Which of the following is the recursive definition for the function f(n)=2n with initial condition f(1) = 2? f(n) = 2n + f(n-1) f(n) = 2n - f(n-1) f(n) = 2n * f(n-1) f(n) = 2f(n − 1) Which of the following is the recursive definition for the function f(n)=5n+2 with initial condition f(1)=7? f(n) = 5n - f(n-1) f(n) = 5f(n-1) + 2 f(n) = 5n + f(n-1) f(n) = f(n-1) + 5
Which of the following is the base case in the recursive function below?def xxx(N):if (N = 0):print(N)else:xxx(N - 1) a. N > 0 b. N = 0 c. N < 0 d. N ≠ 0
please code in python Write a recursive function to add a positive integer b to another number a, add(a, b), where only the unit 1 can be added, For example add(5, 9) will return 14. The pseudocode is: # Base case: if b is 1, you can just return a + 1 # General case: otherwise, return the sum of 1 and what is returned by adding a and b - 1.
Function f grows no slower than function g. O f (n) = O(g(n) O f (n) = 2(g(n)) O f (n) = o(g(n)) O f(n) = O(g(n))
1. Consider the following recursive function: def foo(n): if (n == 0): return 0 return n + foo(n - 1)a. What is foo(5) b. What is foo(10) c. Suppose that n + foo(n - 1) is changed to n * foo(n - 1). What is foo(5) now? d. What happens if foo(-1) is called?
CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021
Suppose the runtime efficiency of an algorithm is presented by the function f(n) = 10n + 10². Which of the following statements are true? Indicate every statement that is true. A. The algorithm is O(n log n) B. The algorithm is O(n) and O(log n). C. The algorithm is O(log n) and 80(n). D. The algorithm is (n) and (log n). E. All the options above are false.
Write a recursive function that, given a sequence of comparable values, returns the count of elements where the current element is less than the following ( next ) element in the given sequence. See the examples given below. def count_ordered ( seq ) : """ Input : A sequence of comparable elements Output : The number of elements that are less than the following element in the sequence Example : >>> count_ordered ( [ 1 , 2 , 3 , 4 , 5 , 6 ] ) 5 >>> count_ordered ( ( 1 , 12, 7.3 , -2,4 ) ) 2 >>> count_ordered ( 'Python' ) 2 >>> count_ordered ( [ 6 ] ) 0 >>> count_ordered ( [ ] ) 0 """ In the first example above , count_ordered ( [ 1,2,3,4,5,6 ] )the returned answer is 5 because for all the first 5 numbers the current number is less than the next number. In the second example above, count_ordered ( ( 1,12,7.3 , -2,4 ) )the…
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In loop functions.py, define a function named permutations that takes two paramters, n and r, in that order. This function returns the number of different permutations of length r from set of size n. Essentially to calculate these permutations, the function should compute the product (n - r+1)*(n-r+2)*(n-r+3)*...*(n-2)*(n-1) or n!/(n-r)!. No if statements or built in math functions should be used. For or while loops are best reccomended.
In program C Write a recursive function find_sum(n)that calculates the sum of successive integers starting at 1and ending at n(i. e., find_sum( n) = 1 + 2 . . .+( n -1) + n.