The following function is designed to determine (the hard way) if a number is prime. What definition for stopNum will complete the function? There are multiple answers that will work in the sense that they will produce the right output. For full marks, your answer must be the one which will both work AND cause the loop to run the FEWEST number of times (thus making the function as fast as possible). def checkPrime(num): factors = [] stopNum for nn in range(2,stopNum): if num % nn == 0: = ??? factors.append(nn) if len(factors): print("The number is composite") alre:

The following function is designed to determine (the hard way) if a number is prime. What definition for stopNum will complete the function? There are multiple answers that will work in the sense that they will produce the right output. For full marks, your answer must be the one which will both work AND cause the loop to run the FEWEST number of times (thus making the function as fast as possible). def checkPrime(num): factors = [] stopNum for nn in range(2,stopNum): if num % nn == 0: = ??? factors.append(nn) if len(factors): print("The number is composite") alre:

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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