What is the best explanation for the observation that the electriccharge on the stem became positive as the charged bee approached (beforeit landed)? Because the earth is a reservoir of large amounts of charge, positive ions were drawn up the stem from the ground toward the charged bee.
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What is the best explanation for the observation that the electric
charge on the stem became positive as the charged bee approached (before
it landed)? Because
the earth is a reservoir of large amounts of charge, positive ions were
drawn up the stem from the ground toward the charged bee.
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- If conductor P, with a positive charge, is placed in contact with another conductor Q (initially uncharged). After contact what will be the nature of the charge on Q? and on P? How do you know this will happen?A 2.6 mm -diameter sphere is charged to -4.5 nC . An electron fired directly at the sphere from far away comes to within 0.38 mm of the surface of the target before being reflected. a)What was the electron's initial speed? b)At what distance from the surface of the sphere is the electron's speed half of its initial value? c)What is the acceleration of the electron at its turning point?In 1910 Rutherford performed a classic experiment in which he directed a beam of alpha particles at a thin gold foil. He unexpectedly observed a few of the particles scattered almost directly backward. This result was not consistent with then current models of atomic structure and led Rutherford to propose the existence of a very dense concentration of positive charge at the center of an atom-the atomic nucleus. The alpha particle has a charge of +2e and the gold nucleus a charge of +79e. Suppose that an alpha particle is initially a great distance from the gold, has a kinetic energy of 5.44 MeV (5.44 x 106 eV), and is headed directly at a gold nucleus. How close will the particle come to the center of the nucleus? Treat the nucleus and the alpha particle as point charges.
- A particle having a positive charge of 1.4 10-6 C experiences an upward force of 3 N when placed at a certain location in space. What is the magnitude and direction of the electric field at that point? magnitude= direction = What would be different about your answer if the particle possessed a negative charge of 1.4 10-6 C? The direction would be rotated 90°.The magnitude would be increased. The magnitude would be decreased.The direction would be reversed.A 2.6mm-diameter sphere is charged to -4.5nC. An electron fired directly at the sphere from far away comes to within 0.38mm of the surface of the target before being reflected. (A) What was the electron's initial speed? (B) At what distance from the surface of the sphere is the electron's speed half of its initial value? (C) What is the acceleration of the electron at its turning point? A 2.6 mm -diameter sphere is charged to -4.5 nC . An electron fired directly at the sphere from far away comes to within 0.38 mm of the surface of the target before being reflected.Please Asap
- The charge per unit length on a long, straight filament is -93.3 µC/m. (a) Find the electric field 10.0 cm from the filament, where distances are measured perpendicular to the length of the filament. (Take radially inward toward the filament as the positive direction.) MN/C(b) Find the electric field 40.0 cm from the filament, where distances are measured perpendicular to the length of the filament. MN/C(c) Find the electric field 120 cm from the filament, where distances are measured perpendicular to the length of the filament. MN/CThe membrane surrounding a living cell consists of an inner and an outer wall that are separated by a small space. Assumne that the membrane acts like a parallel plate capacitor in which the effective charge density on the inner and outer walls has a magnitude of 7.1x 10-6 C/m2.(a) What is the magnitude of the electric field within the cell membrane? (b) Find the magnitude of the electric force that would be exerted on a potassium ion (K*; charge = +e) placed inside the membrane. (a) Number Units (b) Number UnitsYou are given three pith balls. When balls A and B are brought close together (far away from C), the two repel. When A and C are brought close together (far away from B), the two attract. When B and C are brought close together (far away from A), the two attract. Find four solutions for how A, B, and C could be charged (+, - or neutral) relative to one another.
- Two parallel conducting plates are seperated by 1.0 mm and carry equal but opposite charge densities. If the difference between them is 2.0 V, what is the magnitude of the surface charge density on each plate?Levitation: The largest electric field strength you can create in air before dielectric breakdown (a spark) occurs is about 3.0 x 10°V/m. Suppose you created an electric field with this strength – pointing directly upward – between a set of parallel plates that are 9.9cm apart. You want to use this system to levitate water droplets with a mass of 1.8g. (a) How much charge would you have to put on a droplet to make it levitate? (b) Suppose that 43 charged droplets are levitating and the field strength suddenly drops by 24 percent, to about 2.3 x 106 V/m, how quickly would the droplets accelerate? EWhat is the electric field at a point 0.200 m to the right of a +1.50*10^-8 C charge? Include a + or - sign to indicate the direction of the field. (Unit = N/C)