what is its mass?
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A: Ans:- Image-1
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A singly ionized particle is travelling in a helix in a region where there is a uniform magnetic field of strength 1.3T. The helix has a radius of 9.0cm and when viewed from the side, the turns make a 70° “pitch” with respect to the axis of symmetry. If the particle is traveling at 1.2x 106 m/s, what is its mass?
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- A particle with positive charge q = 3.52 x 1018 C moves with a velocity v = (5î + 4ĵ – k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (3î + 2ĵ + k) T and E = (3î - j - 2k) V/m. (Give your answers in N for each component.) Ey = Ey = F, = (b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) ° counterclockwise from the +x-axis (c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) E, = V/m E, = V/m E, = V/mAfter being accelerated to a speed of 1.92×105 m/s , the particle enters a uniform magnetic field of strength 0.800 T and travels in a circle of radius 34.0 cm (determined by observing where it hits the screen as shown in the figure). The results of this experiment allow one to find m/q. Find the ratio m/q for this particle. Express your answer numerically in kilograms per coulomb.Let's take the Earth's magnetic field BE = 1.70 x 10-4 T pointing north. A metal cable attached to a space station stretches by 1.4 km. What would be the potential difference ( ΔΔ V) that develops between the ends of the cable if it’s traveling eastbound around Earth with a speed 4.4 km/s?
- Problem 2: = A particle with charge +2.0 C moves through a uniform magnetic field. At one instant the velocity vector is v (2î+4ĵ + 6k) m/sec and the magnetic force on the particle is F = (41-20ĵ+ 12k) N. The x and y components of the magnetic field are equal (Bx = By). Thus, the magnetic field is given by B = B×î + B×ĵ + B₂k. What are B× and B₂? Answer: Bx = -3 T and B₂ = −4 T.Q. 3: A proton moves through a uniform magnetic field given by B = (30 î – 205) mT. At a time t1, the proton has a velocity given by = the proton is FB (Vz î + (2000m/s)ĵ) and the magnetic force of (4 * 10-17N) k. At that instant, what is the velocity vx?Q. 2: The velocity of an electron at an instant moving in a magnetic field B = (3.0 î + 4.0ĵ)mT is given by v = (300 î – 400ĵ)km/s. Calculate the magnetic force acting on the electron. What is the radius of the electron orbit?