What is [H30*] in a solution of 0.075 M HNO, and 0.030 M NaNO,? HNO, (aq) + H,0 (1) = H;0* (aq) + NO, (aq) K = 4.6 x 105 %3D

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**Problem Statement:**

What is [H₃O⁺] in a solution of 0.075 M HNO₂ and 0.030 M NaNO₂?

**Balanced Chemical Equation:**

HNO₂ (aq) + H₂O (l) ⇌ H₃O⁺ (aq) + NO₂⁻ (aq)
\[ K_a = 4.6 x 10^{-5} \]

**Explanation:**

To find the concentration of hydronium ions ([H₃O⁺]) in the given solution, we need to apply the concept of weak acid equilibrium involving HNO₂ in the presence of its conjugate base NO₂⁻. The acid dissociation constant (\( K_a \)) for nitrous acid (HNO₂) is given, which is crucial for solving this problem.
Transcribed Image Text:**Problem Statement:** What is [H₃O⁺] in a solution of 0.075 M HNO₂ and 0.030 M NaNO₂? **Balanced Chemical Equation:** HNO₂ (aq) + H₂O (l) ⇌ H₃O⁺ (aq) + NO₂⁻ (aq) \[ K_a = 4.6 x 10^{-5} \] **Explanation:** To find the concentration of hydronium ions ([H₃O⁺]) in the given solution, we need to apply the concept of weak acid equilibrium involving HNO₂ in the presence of its conjugate base NO₂⁻. The acid dissociation constant (\( K_a \)) for nitrous acid (HNO₂) is given, which is crucial for solving this problem.
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