What height of mercury column will cause a pressure of 680 kPa? Use sg of mercury equals to 13.6 A 5.10 m В 50 m C) None of the above D 69.32 m

The 50-kg block in the figure is initially at rest on a horizontal plane. Determine the friction force between the block and the surface after P was gradually increased from 0 to 245.25 N. In which phase will the block be classified (Phase 1- no motion, Phase 2 - impending motion, or Phase 3 - in motion)? = 50(9.81) = 490.5 N W 4, = 0.5 H= 0.2 %2D Hint: At which phase will the block be if P-245.25N - Phase 1 (no motion)? Phase 2 (impending motion)? Phase 3 (in motion)? Make use of the coefficient of friction and the normal force to solve for the maximum frictional force.

mathalino.com/reviewer Problem 001 Problem Determine the x and y components of the forces shown below in Fig P-001. F2 = 50 kN F1 = 58 kN 45% 300 F4 = 40 kN 5. 12 F3 = 45 kN Figure P-001 Solution 001 Click here to show or hide the solution Tags: العربية الإنجليزية ...

1. When the force of 3 mN is applied to the plate the line AB in the liquid remains straight and has a velocity of 0.6x10-3 m/s. If the surface area of the plate in contact with the liquid is 0.6 m2, determine the approximate viscosity of the liquid. В B' 3 mN 4 mm A

Utilice el método de castigliano para calcular la deflexion en el nodo C de la viga

Castor oil (SG = 0.96) uiny Problem 9: %3D A tank whose bottom is 18 inches x 18 inches is filled with 2 in. three liquid as shown: 12 inches of carbon (SG=1.59), 4 inches of water and 2 inches of (SG=0.96). Compute the total hydrostatic psi) acting at the bottom of the tank. tetrachloride water 4 in. castor oil Carbon tetrachloride 12 in. pressure (in (SG = 1.59)

answer key : 2.51 x 10^-3 in.

With solution

Complete the following Profile Leveling Notes: (Use 2 decimal places.) STA BS HI FS BM1 0.95 1 2 TP1 3.13 0.64 3 4 5 6 7 TP2 2.16 ? 8 9 10 11 TP3 0.82 2.37 TP4 1.35 3.50 12 BM2 1.24 IFS 3.0 2.3 2.7 2.8 3.1 0.5 0.8 0.9 1.2 1.7 2.8 3.0 ELEV 225.50 ? ? ? 227.66 ? ?

How to get TEC and TBC