please help? Excess H20 AddedSlow/FastSample #Starting MassMass RecoveredМ.Р.(mL)Crystallization1041869|120.0- 120:5O.42349 119.8 -12030:32429|120.7-121:3slow20.5046gfast3D4920g0.49339Slow4fast). 37089 121.9 - 122.70:49109D.3019g122:0-122.710slow10fast0-3472g1a१-122-१Observations:• Thein compan'son tothe fast cooling.slow cooling had alowervangeadded, the nigher theme Hing pointThemovewater thatwasCalculate the % recovery for each sample= massafterx100massbefore#4) 0.37089#1) 0.41869O-4991g83.871.75.17%%0.4933g#5) 0.301990 49109#2) 0.423490:5046983.91%61.49%0#6) 0.3472g6.5014969.25%0#3) 0.32429O.4920965.89%%3D What do the melting points of the 6 samples tell you about their relative purities?

Melting point is the temperature at which equilibrium exist between solid and liquid phases. The…

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What do the melting points of the 6 samples tell you about their relative purities?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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please help?

Excess H20 Added
Slow/Fast
Sample #
Starting Mass
Mass Recovered
М.Р.
(mL)
Crystallization
1
041869|120.0- 120:5
O.42349 119.8 -1203
0:32429|120.7-121:3
slow
2
0.5046g
fast
3
D4920g
0.49339
Slow
4
fast
). 37089 121.9 - 122.7
0:49109
D.3019g
122:0-122.7
10
slow
10
fast
0-3472g
1a१-122-१
Observations:
• The
in compan'son to
the fast cooling.
slow cooling had a
lower
vange
added, the nigher the
me Hing point
The
move
water that
was
Calculate the % recovery for each sample
= mass
after
x100
mass
before
#4) 0.37089
#1) 0.41869
O-4991g
83.871.
75.17%%
0.4933g
#5) 0.30199
0 49109
#2) 0.42349
0:50469
83.91%
61.49%0
#6) 0.3472g
6.50149
69.25%0
#3) 0.32429
O.49209
65.89%
%3D

What do the melting points of the 6 samples tell you about their relative purities?

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