Two batteries supply current to the circuit in the figure. The figure shows the potential difference across two of the resistors and the value of the third resistor.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Two batteries supply current to the circuit in the figure. The figure shows the potential difference across two of the resistors and the value of the third resistor. 

3.0 V
4.5 V
3.5 V
ww
I
m
ww
2.0 V
ww
150 Q
Transcribed Image Text:3.0 V 4.5 V 3.5 V ww I m ww 2.0 V ww 150 Q
Expert Solution
Step 1

Let the current I is flowing to the circuit 

and hence all the resistances are connected in series so the current through all the resistors will be the same so writing the KVL in the loop we get 

4.5+3.0=3.5+150×I+2I=2.0150=0.0133A=133mA

So the current flowing through the circuit will be 133mA.

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what current is supplied by the batteries?

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