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Three resistors with resistances of 500N, 1000, and 15002 are connected in series to a battery.
The power through the 10002 resistor is 100W. Determine the following:
The battery voltage =
The current through the 5002 resistor =
The current through the 1000N resistor =
The current through the 15002 resistor =
The current out of the battery =
The power through the 5002 resistor =
The power through the 1500N resistor =
The total power through the circuit =
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