What conditions must be satisfied by b1, b2, b3, b4, and b5 for the overdetermined linear system x1 – 7x2 = bị x1 – 6x2 = b2 x1 + x2 = b3 %3D - x¡ – 8x2 = b4 %3D - x1 + 9x2 = b5 %3D to be consistent? 15 = r + 17 9 -s, b4 = s, b5 =r 17 16 1 8 bị 17"+ 1プ s, b3 = -r + 17 = r s, b2 15 = r + 1 =-r + 17 16 8 bị 9 -s, b4 = r, b5 = S 17* 17 s, b2 17" + 17 %3D 17 +75, b3 = 15 = r 8. 9 ==r + 17* 17 16 1 bị = r 17" + 17°, b2 17 + 17, b3 s, b4 = r, b5 = s 9 8 =-r + 1 16 15 = r + 2 s, , b4 = r, b5 = S bi 17+ プ s, b2 = r 17 + 17, b3 17 17 16 1 15 bị 17* 1プ 9 s, b4 = r, b5 = s ニード+ -s, b2 s, b3 %3D 17* 17
What conditions must be satisfied by b1, b2, b3, b4, and b5 for the overdetermined linear system x1 – 7x2 = bị x1 – 6x2 = b2 x1 + x2 = b3 %3D - x¡ – 8x2 = b4 %3D - x1 + 9x2 = b5 %3D to be consistent? 15 = r + 17 9 -s, b4 = s, b5 =r 17 16 1 8 bị 17"+ 1プ s, b3 = -r + 17 = r s, b2 15 = r + 1 =-r + 17 16 8 bị 9 -s, b4 = r, b5 = S 17* 17 s, b2 17" + 17 %3D 17 +75, b3 = 15 = r 8. 9 ==r + 17* 17 16 1 bị = r 17" + 17°, b2 17 + 17, b3 s, b4 = r, b5 = s 9 8 =-r + 1 16 15 = r + 2 s, , b4 = r, b5 = S bi 17+ プ s, b2 = r 17 + 17, b3 17 17 16 1 15 bị 17* 1プ 9 s, b4 = r, b5 = s ニード+ -s, b2 s, b3 %3D 17* 17
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:What conditions must be satisfied by b1, b2, b3, b4, and b5 for the overdetermined linear system
x1 – 7x2 = bị
x1 – 6x2 = b2
= b3
-
X1 + x2 =
X1 – 8x2 = b4
-
x1 + 9x2 = b5
to be consistent?
16
1
15
= =r +
17
8
= =r +
17
9
-s, b4 = s, b5 = r
17
bị
-r +
s, b2
s, b3
17
17
17
15
=-r +
17
1
= -r -+
s, b3
17
16
8.
-r +
17
9
s, b4 = r, b5 = S
17
bị
s, b2
17
-
-
17
16
1
2
15
8
9
bị
-r +
s, b2
17
b3
-s, b4 = r, b5 = s
Er +
-r +
S,
17
%D
%D
17
17
17
17
8
9.
16
1
15
2
-S, ,
17
9
-s, b4 = r, b5 = s
17
bị
= Er +E
s, b3
17
b4 = r, b5 = s
-r +
s, b2
-r +
-
-
17
17
16
17
17
1
15
2
8
Er +
s, b3
17
bi
=-r +
s, b2
%3D
%D
17 +175, b4 = r, b5 = s
-
17
17
17
17
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