What concentration of potassium hydroxide is needed to give an aqueous solution with a pH of 11.220? Molarity of potassium hydroxide = M

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### Determining the Concentration of Potassium Hydroxide for a Specific pH

To calculate the concentration of potassium hydroxide (KOH) needed to achieve an aqueous solution with a pH of 11.220, follow the steps below:

1. **Understanding pH**: The pH of a solution is a measure of its acidity or alkalinity. A pH of 7 is neutral, below 7 is acidic, and above 7 is basic (alkaline).

2. **Desired pH**: The target pH for this solution is 11.220.

3. **Relationship Between pH and pOH**: 
   - The sum of pH and pOH for any aqueous solution is always 14.
   - Therefore, \( \text{pOH} = 14 - \text{pH} \). 
   - For a pH of 11.220, \( \text{pOH} = 14 - 11.220 = 2.780 \).

4. **Calculating Hydroxide Ion Concentration**: 
   - The pOH is related to the concentration of hydroxide ions (OH⁻) in the solution by the equation \( \text{pOH} = -\log[\text{OH}^-] \).
   - Rearranging, we get \( [\text{OH}^-] = 10^{-\text{pOH}} \).
   - Substituting the value of pOH, \( [\text{OH}^-] = 10^{-2.780} \).

5. **Molarity of Potassium Hydroxide**:
   - Since KOH is a strong base and dissociates completely in water, the concentration of KOH is equal to the concentration of OH⁻ ions.
   - Therefore, the molarity of potassium hydroxide \( [\text{KOH}] = 10^{-2.780} \) M.

This results in:

**Molarity of potassium hydroxide = (Blank to be filled) M**

Enter the calculated value in the provided blank space for Molarity.
Transcribed Image Text:### Determining the Concentration of Potassium Hydroxide for a Specific pH To calculate the concentration of potassium hydroxide (KOH) needed to achieve an aqueous solution with a pH of 11.220, follow the steps below: 1. **Understanding pH**: The pH of a solution is a measure of its acidity or alkalinity. A pH of 7 is neutral, below 7 is acidic, and above 7 is basic (alkaline). 2. **Desired pH**: The target pH for this solution is 11.220. 3. **Relationship Between pH and pOH**: - The sum of pH and pOH for any aqueous solution is always 14. - Therefore, \( \text{pOH} = 14 - \text{pH} \). - For a pH of 11.220, \( \text{pOH} = 14 - 11.220 = 2.780 \). 4. **Calculating Hydroxide Ion Concentration**: - The pOH is related to the concentration of hydroxide ions (OH⁻) in the solution by the equation \( \text{pOH} = -\log[\text{OH}^-] \). - Rearranging, we get \( [\text{OH}^-] = 10^{-\text{pOH}} \). - Substituting the value of pOH, \( [\text{OH}^-] = 10^{-2.780} \). 5. **Molarity of Potassium Hydroxide**: - Since KOH is a strong base and dissociates completely in water, the concentration of KOH is equal to the concentration of OH⁻ ions. - Therefore, the molarity of potassium hydroxide \( [\text{KOH}] = 10^{-2.780} \) M. This results in: **Molarity of potassium hydroxide = (Blank to be filled) M** Enter the calculated value in the provided blank space for Molarity.
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