Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![What concentration of NO, results when 809 mL of 0.507 M NANO, is mixed with 875 mL of 0.411 M Ca(NO,),?
[NO,] =
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4cbada35-3122-4a6c-a25c-246bca0ae236%2F8fe73ece-1ad4-431b-a762-13c86ec9d3b1%2Ffj84g4ag_processed.png&w=3840&q=75)
Transcribed Image Text:What concentration of NO, results when 809 mL of 0.507 M NANO, is mixed with 875 mL of 0.411 M Ca(NO,),?
[NO,] =
M
Expert Solution

Step 1
Here we are mixing NaNO3(aq) and Ca(NO3)2(aq).
Both NaNO3(aq) and Ca(NO3)2(aq) are completely dissolved in water to give respective ions.
1 mol NaNO3(aq) is dissolved in water to form 1 mol Na+(aq) and 1 mol NO3-(aq).
Hence mole ratio = 1/1
Since the coefficient of NO3 in Ca(NO3)2(aq) is 2,
1 mol Ca(NO3)2(aq) is dissolved in water to form 1 mol Ca2+(aq) and 2 mol NO3-(aq).
Hence mole ratio = 2/1
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