Could you please write me a brief summary about the results that I have and it's about the standardization of sodium hydroxide thank you **Laboratory 10: Standardization of a Sodium Hydroxide Solution****Standardization of Sodium Hydroxide - Report Sheet**- **Name:** ____________________- **Date:** ____________________- **Lab Section:** ____________________- **Hood Number:** ____________________| | | | ||------------------|----|----|----------------------|| Notebook | /10| | || Technique | /10| | || Report Sheets | /80| | TOTAL /100 |---### Standardization of a Sodium Hydroxide SolutionYou must show calculations for 3, 4, 5, and 7 for credit.#### A. Preparation of standard KHp (potassium hydrogen phthalate, KHC₈H₄O₄) solution1. **Mass of KHp used:** 9.064 g2. **Molecular weight of KHp:** 204.23 g/mol3. **Moles of KHp used in 250 mL of solution:** 0.0088 moles4. **Molarity of the KHp solution:** 0.3414 M#### B. Standardization of the NaOH solution5. **Moles of KHp in 20.00 mL of KHp solution used for titration:** 3.25 moles**Volumes of your NaOH solution used to titrate this 20.00 mL of acid. Best two trials for each student:**| Your Results | Partner’s Results ||---------------|-------------------|| **Trial 1** | || 14.30 mL | 16.35 mL || **Trial 2** | || 19.47 mL | 13.33 mL |Note: The table above represents the volume of NaOH solution used in the titration trials, indicating the students' results versus their partner's results. **Best Value**14.84 mL6. **Explain how you arrived at your best value.**7. **Molarity of your NaOH solution:**0.22---6. The purpose of executing trials in quantitative analysis is to find the deviation in the results. The lesser the deviation between the values obtained in trials, the precise the result is. In the case of my result, the difference between the results obtained in Trial 1 and Trial 2 is 16.35 mL - 13.33 mL = 3.02 mL. But in the case of my partner’s result, the difference between the results obtained in Trial 1 and Trial 2 is 19.47 mL - 14.30 mL = 5.17 mL. There appears relatively large deviation in my partner’s result. My result is better than my partner’s result. The average of my result = (16.35 mL + 13.33 mL) / 2 = 29.68 mL / 2 = 14.84 mL.---

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Answered: Could you please write me a brief…

Could you please write me a brief summary about the results that I have and it's about the standardization of sodium hydroxide

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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