What change in entropy occurs when a 0.12 kg steam at 121 deg C is transformed into ice at -28 deg C? Use the 2nd law of thermodynamics to explain calculated result.

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What change in entropy occurs when a 0.12 kg steam at 121 deg C is transformed into ice at -28 deg C?

Use the 2nd law of thermodynamics to explain calculated result.

Expert Solution
Step 1: Introduction

The mass of the steam: m equals 0.12 space kg

The initial temperature of the steam: T subscript s equals 121 degree straight C equals 373 space straight K

The final temperature of the ice: T subscript i equals negative 28 degree straight C equals 245 space straight K

Specific heat capacity of steam: S subscript s equals 1.996 space kJ divided by kg. straight K

Specific heat capacity of water: S subscript w equals 4.182 space kJ divided by kg. straight K

Specific heat capacity of ice: S subscript i equals 2.093 space kJ divided by kg. straight K

Latent heat of ice: L subscript i equals 336 space kJ divided by kg

Latent heat of steam: L subscript s equals 2257 space kJ divided by kg

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