Consider the following problem, which is the Hydit-Filit problem with one of the constraints removed. Max: Z(x)= 140x₁+ 160 x2 s.t. 5x,+ X1 XI 5x2 ≤ 50 ≤8 X2 6 ≥ 0 X2 ≥ 0 I find that the optimal solutions is x* = (4, 6). (U₁) (U₂) (U3) (U4) (us)

Q: 43=31-5(1-5w)

A: Given that,   43 = 31 - 5(1-5w) We have to solve for w.

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A: apply the sum

Q: Which expression is equivalent to162   Question 6 options:   6¯10 • 68…

A: This expression is not equivalent to 162.

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A:

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A: given that,   what is 60 plus 60?

Q: Which expressions are equivalent to  -8z + (-5.5) + 2.5z + 3y - 3.5

A:

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A:

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A: Given that: a0=1

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Q: y = 3x О 75 X = 25 y = о 325

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A:

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A: We have to find the value

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A:

Q: Let A = -1 -9 3

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Q: What do you mean by 50C2

A: From the given question, The value of n is, 50 The value of r is, 2

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A: Probability = favorable/total  Total balls = 8  Numbered from 1 to 8

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Q: what about b, thanks

A:

Q: What are the values of u5 and u1?

A: This is the problem of optimisation.

Q: what expression would be equivalent to?

A: If you have any problem let me know here in comment box for this thankyou.

Q: What is the value of -6a b for a =-2 and b = 4? O A. 768 O B. 12 O C.-12 O D.-768

A:

Q: How do you know when to put 1 or 0 in the chart in the dummy variable approach

A: How it is known that  or  must be put in the chart in the dummy variable approach must be…