What are the concentrations of H,O* and OH¯ in oranges that have a pH of 3.77?[H,O*] = 1.999 x10¬4MIncorrect= [-HO]5.0 х10-11MIncorrect

pH of a solution is given by the negative logarithm of proton. Write the expression. pH=-log[H+] Solve for [H+]. [H+]=10-pH Substitute 3.77 for pH to calculate H+. [H+]=10-3.77 =1.7×10-4 Therefore, the concentration of H+ is 1.7×10-4 M. Write the relation between pH and pOH. pH + pOH = 14 Solve for pOH. pOH = 14 -pH Substitute 3.77 for pH to calculate pOH. pOH = 14 -3.77 =10.23 Therefore, the pOH is 10.23. Write the expression for pOH. pOH = -log [OH-] Solve for [OH-]. [OH-]=10-pOH Substitute 10.23 for pOH to calculate [OH-]. [OH-]=10-10.23 =1.69×1010 Therefore, the [OH-] is 1.69×1010.

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What are the concentrations of H,o* and OH¯ in oranges that have a pH of 3.77? [H,O*] = 1.999 x10° M Incorrect [OH¯] = 5.0 x10¬11 M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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