Weight of Antacid 1.541 g Concentration of HCl used 0.500 M Vol HCl added (mL) 49.67 mL Concentration of NaOH 0.453 M Total moles of HCl added 9.02 Moles HCl = Molarity x volume in liters Initial buret reading (NaOH) 25.65 mL Final buret reading (NaOH) 49.72 mL Vol NaOH added (mL) Final -Initial buret readings (NaOH) Moles of NaOH used Moles NaOH used = Molarity x volume in L Moles of HCl neutralized by NaOH 10.90x103 moles Moles of HCl neutralized by NaOH = moles NaOH (1mole acid/1 mole base) Moles of HCl neutralized by antacid Moles of HCl neutralized by the antacid = total moles HCl added – moles HCl neutralized by NaOH Moles of HCl consumed per gram of antacid Moles of HCl consumed per gram of antacid= moles HCl neutralized by antacid/ grams of antacid subtract the moles of HCl nuetralized by the NaOh from the total moles of HCl added to get the moles of HCl neutralized by the antacid
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Trial 1 |
Calculations |
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Weight of Antacid
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1.541 g |
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Concentration of HCl used |
0.500 M |
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Vol HCl added (mL) |
49.67 mL |
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Concentration of NaOH |
0.453 M |
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Total moles of HCl added |
9.02 |
Moles HCl = Molarity x volume in liters |
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Initial buret reading (NaOH) |
25.65 mL |
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Final buret reading (NaOH) |
49.72 mL |
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Vol NaOH added (mL) |
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Final -Initial buret readings (NaOH) |
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Moles of NaOH used |
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Moles NaOH used = Molarity x volume in L |
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Moles of HCl neutralized by NaOH |
10.90x103 moles |
Moles of HCl neutralized by NaOH = moles NaOH (1mole acid/1 mole base) |
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Moles of HCl neutralized by antacid |
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Moles of HCl neutralized by the antacid = total moles HCl added – moles HCl neutralized by NaOH |
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Moles of HCl consumed per gram of antacid |
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Moles of HCl consumed per gram of antacid= moles HCl neutralized by antacid/ grams of antacid |
subtract the moles of HCl nuetralized by the NaOh from the total moles of HCl added to get the moles of HCl neutralized by the antacid
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