We would like to determine the sample size necessary to ensure a probability of atype I error of 0.025 and a probability of a type II error of 0.05 at μ = 65whentestingHo : μ = 60H : μ > 60and we have a random sample of size n from N(μ, 100), n is equal to59485244

Given: Type I error (α)=0.025Type II error (β)=0.05Variance(σ2)=100standard deviation(σ)=10μ0=65…

Answered: We would like to determine the sample…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The test statistic for testing Họ: u = 100 against Ha: u z 100 was t = 3.3, with P-value 0.001. Which of the following is the appropriate conclusion? Since the P-value is very small, we are unable to conclude that u = 100. In order to interpret the results, we must first know the sample size. Since the P-value is very small, we conclude that µ ± 100. Since the P-value is very small, we are unable to conclude that u # 100. Since the P-value is very small, we conclude that u = 100.
Test the claim about the difference between two population means mu 1μ1 and mu 2μ2 at the level of significance alphaα. Assume the samples are random and independent, and the populations are normally distributed. Claim: mu 1μ1equals=mu 2μ2; alphaαequals=0.01 Population statistics: sigma 1σ1equals=3.3, sigma 2σ2equals=1.5 Sample statistics: x overbar 1x1equals=17, n1equals=29, x overbar 2x2equals=19, n2equals=28 Determine the alternative hypothesis. Upper H Subscript aHa: mu 1μ1 ▼ not equals≠ greater than or equals≥ less than or equals≤ greater than> less than< mu 2μ2 Determine the standardized test statistic. zequals=nothing (Round to two decimal places as needed.) Determine the P-value. P-valueequals=nothing (Round to three decimal places as needed.) What is the proper decision? A. Reject Upper H 0H0. There is enough evidence at the 1% level of significance to reject the claim. B. Fail to reject Upper H 0H0. There is not…
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Test the claim about the difference between two population means µ₁ and µ₂ at the level of significance a. Assume the samples are random and independent, and the populations are normally distributed. Claim: μ₁ μ₂; α=0.10. Assume o² #02 Sample statistics: x₁=2404, s₁ = 177, n₁ = 15 and x₂ = 2299, s₂ = 54, n₂ = 10 Identify the null and alternative hypotheses. Choose the correct answer below. A. Ho: ₁ = ₂ Hai Mi#H2 C. Ho: H₁ H₂ Hai HSM2 E. Ho: H₁ H₂ Ha: ₁ = ₂ Find the standardized test statistic t. t= (Round to two decimal places as needed.) Find the P-value. P= (Round to three decimal places as needed.) Decide whether to reject or fail to reject the null hypothesis and interpret the decision in the context of the original claim. Ho. There enough evidence at the 10% level of significance to reject the claim. B. Ho: H₁ H₂ Ha: ₁ H2
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The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let u denote the true average reflectometer reading for a new type of paint under consideration. A test of Ho: μ = 20 versus H₂: μ> 20 will be based on a random sample of size n from a normal population distribution. What conclusion is appropriate in each of the following situations? (Round your P-values to three decimal places.) USE SALT (a) n = 17, t = 3.1, a = 0.05 P-value = State the conclusion in the problem context. O Do not reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20. O Reject the null hypothesis. There is not sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20. ● Reject the null hypothesis. There is sufficient evidence to conclude that the new paint has a reflectometer reading higher than 20. O Do not reject the null hypothesis. There is not sufficient…
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We would like to determine the sample size necessary to ensure a probability of a type I error of 0.025 and a probability of a type II error of 0.05 at μ = 65when testing Ho : μ = 60 Η : μ > 60 and we have a random sample of size n from N(μ, 100), n is equal to 59