We wish to select a heat exchanger which will yield & = 0.75, using stainless steel fin materials. Calculate the UA required to obtain & = 0.75. Calculate UA by e-NTU methods and state why the LMTD method is difficult to use. For the & -NTU methods, first use the graphical method and then the equation.
We wish to select a heat exchanger which will yield & = 0.75, using stainless steel fin materials. Calculate the UA required to obtain & = 0.75. Calculate UA by e-NTU methods and state why the LMTD method is difficult to use. For the & -NTU methods, first use the graphical method and then the equation.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Heat Exchangers
Heat exchangers are the types of equipment that are primarily employed to transfer the thermal energy from one fluid to another, provided that one of the fluids should be at a higher thermal energy content than the other fluid.
Heat Exchanger
The heat exchanger is a combination of two words ''Heat'' and ''Exchanger''. It is a mechanical device that is used to exchange heat energy between two fluids.
Question
Transcribed Image Text:Turbine Exhaust
Temperature (°F)
Pressure (psia)
Flow rate (lbm/hr)
Density (lbm/ft³)
Specific heat (Btu/lbm °F)
0.259
A cross flow plate fin compact heat exchanger is to be used for this heat recovery
application.
805
16.1
196,000
Compressor Discharge
0.0316
347
132
193,000
0.4380
0.251
Transcribed Image Text:We wish to select a heat exchanger which will yield & = 0.75, using stainless steel fin materials.
Calculate the UA required to obtain & = 0.75. Calculate UA by e-NTU methods and state why
the LMTD method is difficult to use. For the & -NTU methods, first use the graphical method
and then the equation.
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