We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 86 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county. Express your answer in tri-inequality form. Give your answers as decimals, to three places.

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**Estimation of Parent Population in a County**

We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 86 had kids. Based on this, construct a 90% confidence interval for the proportion \( p \) of adult residents who are parents in this county.

**Instructions:**

1. **Tri-Inequality Form:** Express your answer in tri-inequality form. Provide your answers as decimals, to three places.

   \[ \_\_\_\_\_\_ < p < \_\_\_\_\_\_ \]

2. **Point Estimate and Margin of Error Form:** Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.

   \[ p = \_\_\_\_\_\_ \pm \_\_\_\_\_\_ \]
Transcribed Image Text:**Estimation of Parent Population in a County** We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 86 had kids. Based on this, construct a 90% confidence interval for the proportion \( p \) of adult residents who are parents in this county. **Instructions:** 1. **Tri-Inequality Form:** Express your answer in tri-inequality form. Provide your answers as decimals, to three places. \[ \_\_\_\_\_\_ < p < \_\_\_\_\_\_ \] 2. **Point Estimate and Margin of Error Form:** Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places. \[ p = \_\_\_\_\_\_ \pm \_\_\_\_\_\_ \]
Expert Solution
Step 1: Given

n=200

x=86

Sample proportion 

table row cell p with hat on top end cell equals cell 86 over 200 end cell row blank equals cell 0.43 end cell end table

The level of significance is 0.10 (=1–0.90). Using Excel formula “=NORM.S.INV(1-(0.1/2))”, the critical value for 90% confidence level is obtained as 1.645.

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