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We want to find the dimensions of the rectangle with the largest area that can be inscribed in the parabola of equation y = 4 - x and the x-axis as shown in the following figure: If x and y represent the dimensions of the inscribed rectangle shown, then by using the method of the Lagrange multipliers, the lagrangian L corresponds to A) L(x, y, ) = xy – (x² + 4y – 16). B) L(x, y, A) = 2æy – \(x² + y – 4). C) L(x, y, A) = xy – \(2x² + 2y – 8).

We want to find the dimensions of the rectangle with the largest area that can be inscribed in the parabola of equation y = 4 - x and the x-axis as shown in the following figure: If x and y represent the dimensions of the inscribed rectangle shown, then by using the method of the Lagrange multipliers, the lagrangian L corresponds to A) L(x, y, ) = xy – (x² + 4y – 16). B) L(x, y, A) = 2æy – \(x² + y – 4). C) L(x, y, A) = xy – \(2x² + 2y – 8).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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We want to find the dimensions of the rectangle with the largest area that can be inscribed in the parabola of equation y = 4 - x² and the x-axis as shown in the following figure: If x and y represent the dimensions of the inscribed rectangle shown, then by using the method of the Lagrange multipliers, the lagrangian L corresponds to A) L(x, y, A) = xy – (x² + 4y – 16). - B) L(x, y, A) = 2.xy – (x² + y – 4). C) L(x, y, A) = xy – X(2x² + 2y – 8). D) L(x, y, X) = xy – \(x² + 2y – 8).
Transcribed Image Text:We want to find the dimensions of the rectangle with the largest area that can be inscribed in the parabola of equation y = 4 - x² and the x-axis as shown in the following figure: If x and y represent the dimensions of the inscribed rectangle shown, then by using the method of the Lagrange multipliers, the lagrangian L corresponds to A) L(x, y, A) = xy – (x² + 4y – 16). - B) L(x, y, A) = 2.xy – (x² + y – 4). C) L(x, y, A) = xy – X(2x² + 2y – 8). D) L(x, y, X) = xy – \(x² + 2y – 8).
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