We toss a die twice and the possible outcomes are (i, j) where i and j are numbers 1, 2, 3, 4, 5, 6 corresponding to the side that faces up. What is the probability p that i + j = 6, provided that at least one of i and j is even? p = 0.0741 How was the correct answer of 0.0741 attained?
We toss a die twice and the possible outcomes are (i, j) where i and j are numbers 1, 2, 3, 4, 5, 6 corresponding to the side that faces up. What is the probability p that i + j = 6, provided that at least one of i and j is even? p = 0.0741 How was the correct answer of 0.0741 attained?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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How was the correct answer of 0.0741 attained?
Transcribed Image Text:We toss a die twice and the possible outcomes are (i, j) where i and j are numbers 1, 2, 3, 4, 5, 6 corresponding to the side that faces
up. What is the probability p that i + j = 6, provided that at least one of i and j is even?
p = 0.0741
How was the correct answer of 0.0741 attained?
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