We now know the moles of hydroxide used in the titration. But, remember that, of the 100 mL of solution made from the ashes, only 20 mL were used for the titration. What is the total amount of hydroxide produced by the ashes? Volume HCl used: 5.44 mL Concentration HCl solution = 0.10 M 5.44 x 10-4 mol HCl used 5.44 x 10-4 mol OH in 20 mL solution X mol OH- resubmit total mol OH = 100 mL solution X Incorrect 5.44 x 104 mol 20 mL solution
We now know the moles of hydroxide used in the titration. But, remember that, of the 100 mL of solution made from the ashes, only 20 mL were used for the titration. What is the total amount of hydroxide produced by the ashes? Volume HCl used: 5.44 mL Concentration HCl solution = 0.10 M 5.44 x 10-4 mol HCl used 5.44 x 10-4 mol OH in 20 mL solution X mol OH- resubmit total mol OH = 100 mL solution X Incorrect 5.44 x 104 mol 20 mL solution
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:We now know the moles of hydroxide used in the titration. But, remember that, of the 100 mL of solution made from the ashes, only 20 mL
were used for the titration. What is the total amount of hydroxide produced by the ashes?
Volume HCl used: 5.44 mL
Concentration HCl solution = 0.10 M
5.44 x 104 mol HCl used
5.44 x 104 mol OH in 20 mL solution
X mol OH-
resubmit
total mol OH = 100 mL solution x
Incorrect
5.44 x 104 mol
20 mL solution
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