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We need to separate the two beams and draw a Free-Body diagram for each body. Each of the triangular distributed loads has been replaced by a equivalent single force R at the appropriate distance (d, or d2). Calculate R, d, and d2. d, R C, R 30 kN A, 3.5 m 3.5 m 2.5 2.5 -5.0 m 1.5 m A, B, C, D, Answers: R = kN d =

We need to separate the two beams and draw a Free-Body diagram for each body. Each of the triangular distributed loads has been replaced by a equivalent single force R at the appropriate distance (d, or d2). Calculate R, d, and d2. d, R C, R 30 kN A, 3.5 m 3.5 m 2.5 2.5 -5.0 m 1.5 m A, B, C, D, Answers: R = kN d =

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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### Problem Statement Determine the magnitudes of the reactions at \( A, B, \) and \( D \) for the pair of beams connected by the ideal pin at \( C \) and subjected to the concentrated and distributed loads. - **Diagram**: - A beam system with points \( A, B, C, \) and \( D \). - A 30 kN downward force at point \( A \). - A triangular distributed load of 3.4 kN/m from points \( B \) to \( D \). - Distances are marked as follows: - \( A \) to \( B \): 3.5 m - \( B \) to \( C \): 2.5 m - \( C \) to hinge: 5.0 m - Hinge to \( D \): 1.5 m ### Part 1 We need to separate the two beams and draw a Free-Body diagram for each body. Each of the triangular distributed loads has been replaced by an equivalent single force \( R \) at the appropriate distance (\( d_1 \) or \( d_2 \)). Calculate \( R, d_1, \) and \( d_2 \). - **Free-Body Diagrams**: - **Left Beam**: - \( A_x \) and \( A_y \) are the reaction forces at \( A \). - 30 kN downward force. - \( R \) is equivalent force from the triangle. - \( C_y \) is the reaction at \( C \). - \( d_1 \) is the distance of \( R \). - **Right Beam**: - \( C_y \) and \( D_y \) are reaction forces. - \( R \) is the equivalent force from the triangle. - \( d_2 \) is the distance of \( R \). - **Answers**: - \( R = \) [input box] kN - \( d_1 = \) [input box] m
Transcribed Image Text:### Problem Statement Determine the magnitudes of the reactions at \( A, B, \) and \( D \) for the pair of beams connected by the ideal pin at \( C \) and subjected to the concentrated and distributed loads. - **Diagram**: - A beam system with points \( A, B, C, \) and \( D \). - A 30 kN downward force at point \( A \). - A triangular distributed load of 3.4 kN/m from points \( B \) to \( D \). - Distances are marked as follows: - \( A \) to \( B \): 3.5 m - \( B \) to \( C \): 2.5 m - \( C \) to hinge: 5.0 m - Hinge to \( D \): 1.5 m ### Part 1 We need to separate the two beams and draw a Free-Body diagram for each body. Each of the triangular distributed loads has been replaced by an equivalent single force \( R \) at the appropriate distance (\( d_1 \) or \( d_2 \)). Calculate \( R, d_1, \) and \( d_2 \). - **Free-Body Diagrams**: - **Left Beam**: - \( A_x \) and \( A_y \) are the reaction forces at \( A \). - 30 kN downward force. - \( R \) is equivalent force from the triangle. - \( C_y \) is the reaction at \( C \). - \( d_1 \) is the distance of \( R \). - **Right Beam**: - \( C_y \) and \( D_y \) are reaction forces. - \( R \) is the equivalent force from the triangle. - \( d_2 \) is the distance of \( R \). - **Answers**: - \( R = \) [input box] kN - \( d_1 = \) [input box] m
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