We need to find the mass of Ca(OH₂) required to add in pond to make the pH to 7 from 4.29. This question belongs to ionic equilibrium and can solve using the equation of pH.
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@We know that,
So,
ASK
Step 1
We need to find the mass of Ca(OH₂)
required to add in pond to make the pH to 7
from 4.29. This question belongs to ionic
equilibrium and can solve using the
equation of pH.
pH = -log [H+]
|||
Concentration of [H*] in the pond is,
[H*] = 10-PH
[H+] = 10-2.4
[H] = 5.13 × 10-5 M
And the volume of the pond is,
=
LTE 4G ill
+3
Since,
H+ + OH¯--
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Step 3
Hence the number of moles of H* in the
pond will be,
n=MxV
V = 1.75 × 105 m³ = 1.75 × 108 L
X
-‒‒‒‒‒> > H₂O ;
n = 5.13 x 10-5 × 1.75 x 108 moles
n = 8975 moles
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