We need the following definition for part (3) below. Vector spaces V and W are isomorphic if there is a linear transformation φ: V → W that is a bijection, in the sense that (i) φ(u) = φ(v) ⇒ u = v for all u, v∈V; and (ii) for all w ∈ W there exists v ∈ V such that φ(v)=w. Consider the set P2 := {f : R → R : f (x) = ax2 + bx + c for some a, b, c ∈ R}. So P2 is the set of polynomials of degree up to 2. This set is a vector space over R under addition given by (a1x2 +b1x+c1)+(a2x2 +b2x+c2) = (a1 +a2)x2 +(b1 +b2)x+(c1 +c2), and scalar multiplication given by λ(ax2 +bx+c) = λax2 + λbx + λc. Consider the function D : P2 → P2 given by D(ax2 + bx + c) = 2ax + b. Why did I call this function D? Prove that D is a linear transformation1. Find an n such that P2 is isomorphic to Rn. (Don’t just state the value of n; prove why the vector spaces are isomorphic.)
We need the following definition for part (3) below.
(i) φ(u) = φ(v) ⇒ u = v for all u, v∈V; and
(ii) for all w ∈ W there exists v ∈ V such that φ(v)=w.
Consider the set P2 := {f : R → R : f (x) = ax2 + bx + c for some a, b, c ∈ R}.
So P2 is the set of polynomials of degree up to 2. This set is a vector space over R under addition given by
(a1x2 +b1x+c1)+(a2x2 +b2x+c2) = (a1 +a2)x2 +(b1 +b2)x+(c1 +c2),
and scalar multiplication given by
λ(ax2 +bx+c) = λax2 + λbx + λc.
Consider the function D : P2 → P2 given by D(ax2 + bx + c) = 2ax + b.
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Why did I call this function D?
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Prove that D is a linear transformation1.
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Find an n such that P2 is isomorphic to Rn. (Don’t just state the value of n; prove why the vector spaces are isomorphic.)
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