We have this situation: Ho: P1 - P2 = 0, Ha: Pi – P2 # 0 a = 0.10 %3D ni = 500 %3D n2 = 523 What critical value forms the rejection region?
We have this situation: Ho: P1 - P2 = 0, Ha: Pi – P2 # 0 a = 0.10 %3D ni = 500 %3D n2 = 523 What critical value forms the rejection region?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:### Understanding Hypothesis Testing in Statistics
In this example, we are analyzing a hypothesis test for the difference between two proportions.
#### The Hypotheses
- Null Hypothesis (H₀): \( p_1 - p_2 = 0 \)
- Alternative Hypothesis (Hₐ): \( p_1 - p_2 \neq 0 \)
This test is to determine if there is a significant difference between the two population proportions (\( p_1 \) and \( p_2 \)).
#### Parameters Given
- Significance level (\( \alpha \)): 0.10
- Sample size for population 1 (\( n_1 \)): 500
- Sample size for population 2 (\( n_2 \)): 523
#### Determining the Critical Value
The question asks: **What critical value forms the rejection region?**
Let's break down the answer choices provided:
- \( t = 1.645 \)
- \( z = -1.645 \)
- \( z = -1.645, z = 1.645 \)
- \( t = -1.645, t = 1.645 \)
Since the hypothesis involves comparing proportions, the appropriate test is a Z-test (rather than a T-test). The correct critical values, considering the two-tailed nature of our test (due to \( \neq \) in \( H_a \)), are based on the Z-distribution.
For a significance level of 0.10 in a two-tailed test, the critical values are:
- \( z = -1.645 \)
- \( z = 1.645 \)
Therefore, the correct answer is:
- \( z = -1.645, z = 1.645 \)
This option correctly represents the critical values for the rejection region in a two-tailed Z-test with an alpha level of 0.10.
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