We have f(x): f(x) = {sin2x 0 >ܝ TT 2

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
We have f(x):
Jsin2x
< x <
2
2
-
-
f(x) =
0. w.
a)find the coefficients and show that Vx E [-n,1]:
(-1)*
(2k – 3)(2k + 1)
1
4
f(x) =sin2x
-sin(2k – 1) x
n=1
b)with use of parseval identity show that :
1
-2
Z (2k – 3)²(2k + 1)²
64
k=1
Transcribed Image Text:We have f(x): Jsin2x < x < 2 2 - - f(x) = 0. w. a)find the coefficients and show that Vx E [-n,1]: (-1)* (2k – 3)(2k + 1) 1 4 f(x) =sin2x -sin(2k – 1) x n=1 b)with use of parseval identity show that : 1 -2 Z (2k – 3)²(2k + 1)² 64 k=1
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