Compute the derivative of the given function. sin ¹(³+4) O O O d dx d dx d dx [sin ¹(x³ + 4)] = [sin ¹(₁³+ 4)] = -[sin¯¹(x³ + 4)] = d dx Isin -[sin¯¹(x^³ + 4)] = 1 √1-(x-² 1- (x^² + 4)² (x² + 4) 1 (43 √1+ (x³+4)2 (312) 3x-² 1- (x³ + 4)² 1 √ 1 − (x²³ + 4)2 (3x-²) =

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