We have found the values of t for which v(t) s 0 and v(t) 2 0, so we can write the definite integral of |v(t)| as the sum of two integrals. |(t)| dt = 19t – 4| dt 4/9 - L-** ["-( - a (9t - 4) dt + dt 4/9 (9t - 4) dt - dt
We have found the values of t for which v(t) s 0 and v(t) 2 0, so we can write the definite integral of |v(t)| as the sum of two integrals. |(t)| dt = 19t – 4| dt 4/9 - L-** ["-( - a (9t - 4) dt + dt 4/9 (9t - 4) dt - dt
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![We have found the values of t for which v(t) s 0 and v(t) 2 0, so we can write the definite integral of |v(t)| as the sum of two integrals.
'3
|(t)| dt =
19t – 4| dt
4/9
(9t - 4) dt +
dt
- L
4/9
dt
(9t - 4) dt -
4/9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F736401a9-9832-4682-87bf-2cec5da03f32%2F9e0239ab-8379-44ec-93db-cf2075e85f78%2Fmbk92i_processed.png&w=3840&q=75)
Transcribed Image Text:We have found the values of t for which v(t) s 0 and v(t) 2 0, so we can write the definite integral of |v(t)| as the sum of two integrals.
'3
|(t)| dt =
19t – 4| dt
4/9
(9t - 4) dt +
dt
- L
4/9
dt
(9t - 4) dt -
4/9
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