Write the following expression in algebraic form: sin(arccos (6x)) V1-36z2 O VI – 36x² O VI – 6x² O 1+ 36x²

Q: Divide (3 - 4i)/(4 + 3i) and express the result in standard form.

A: Multiply by the conjugate of the denominator

Q: PWrite the following numbers in a + bi form: -1- 3i (a) 5 – i + i, | 4 -5 + (b) + i, 2i 4i (c)…

A: a Given expression is −1−3i5−i. We have to write the given expression in a+bi form. Rationalize the…

Q: Write the product as a sum: 18 cos(25v)cos(6v)

A:

Q: Establish the identity. (csc a- sec B) +(sec ß+ csc a)( sec B- csc a) = -2 sec B(csc a- sec B)…

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Q: 6cis (π/2)/ 12cis (π/8) Divide. Leave your answer in trigonometric form.

A:

Q: Simplify the expression to a + bi form: (-6 – 9i)(-11 +7i)

A:

Q: Simplify the expression to a + bi form: (-8 — 2:) + (8 — і)

A: (- 8 - 2i) + (8 - i) = (- 8 + 8) + (- 2i - i) = 0 + (- 3)i  So, a = 0 &, b = - 3

Q: Divide and express the result in standard form: 5i /(2 - i)

A: The given expression is 5i2-i

Q: Express the following expression in complex exponential form: v=20sin (1000t-30°)

A: To express the following expression in complex exponential form. v=20 sin1000t-30°

Q: Divide and express the result in standard form: (7 + 4i) / (2 - 5i).

A: 7+4i2-5i

Q: Simplify the expression to a + bi form: (5 + 2i)(8 + 8i)

A: (5+2i)(8+8i) = 24 + 56i  The detailed solution is as follows below

Q: |Write the following numbers in a + bi form: -2 – 5i (a) -1+ 2i + i, -1 -5 + 3i (b) i, 5i (c) (–5i)³…

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Q: -1 2x -бу -3 3 -1 -8y U Xu Use only positive exponents in your answer.

A:

Q: Write the following numbers in a + bi form: -1 - 4i + i, -2 – 3i 1 -3 + i, 3i 4i =) (i)³ + i. +

A: Topic:- complex number algebra

Q: Simplify the expression to a + bi form: (1+ 7i) + (4 – 10i) -

A: The given expression is 1+7i+4-10i.

Q: Simplify the expression to a + bi form: (-9 – 8i) – (–4+ 5i)

A: We will express this expression in the standard form of complex number a+ ib. We will add real and…

Q: Find the product and write the result in standard form: (7 - 5i)(-2 - 3i)

A: Given: z=7-5i-2-3i given product can be find as below z=7-5i-2-3i=7-2-3i-5i-2-3i=-14-21i+10i+15i2…