We have found the following Maclaurin series. x4n 142n (2n)! Now we can use this to find the Maclaurin series of the given function, treating the term 13x as a constant and using the rule can = cªn. f(x) = 13x cos 05 (1141+²2) cos(4x²) = (-1)^- n = 0 = 13x ‹ Ë (−1)”. n = 0 = - Σ n = 0 (-1)". x4n 142n (2n)! 4n+1 142 (2n)! X

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