We have determined the following. Sct. (t - 1)e-st dt = (t-1)e-st e-st + C S 5² This allows us to evaluate the improper integral and find L{f(t)}, such that s > 0. The result is a function of s. L{F(t)} = 2 [° (t-1)e-st dt 00 e-st 1 - ² (- (t-1)e-st - S (s > 0)
We have determined the following. Sct. (t - 1)e-st dt = (t-1)e-st e-st + C S 5² This allows us to evaluate the improper integral and find L{f(t)}, such that s > 0. The result is a function of s. L{F(t)} = 2 [° (t-1)e-st dt 00 e-st 1 - ² (- (t-1)e-st - S (s > 0)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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