We have determined the following. Sct. (t - 1)e-st dt = (t-1)e-st e-st + C S 5² This allows us to evaluate the improper integral and find L{f(t)}, such that s > 0. The result is a function of s. L{F(t)} = 2 [° (t-1)e-st dt 00 e-st 1 - ² (- (t-1)e-st - S (s > 0)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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We have determined the following.
f(t
(t - 1)e-st dt = -
(t-1)e-st
e-st
+ C
s²
This allows us to evaluate the improper integral and find L{f(t)}, such that s > 0. The result is a function of s.
L{f(t)} = ²√₁
= 2/² (t-1
(t - 1)e-st dt
00
-26-² (t-1)e-st
=
S
-st
(s > 0)
Transcribed Image Text:We have determined the following. f(t (t - 1)e-st dt = - (t-1)e-st e-st + C s² This allows us to evaluate the improper integral and find L{f(t)}, such that s > 0. The result is a function of s. L{f(t)} = ²√₁ = 2/² (t-1 (t - 1)e-st dt 00 -26-² (t-1)e-st = S -st (s > 0)
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