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An equation of the line tangent to the graph,of f (x) = x(1– 2.x)' at the point (1,–1) is D y = 7x -8 Oy = 2x-3 O y = -7x +6 O y = -2x O y = -6x + 5

An equation of the line tangent to the graph,of f (x) = x(1– 2.x)' at the point (1,–1) is D y = 7x -8 Oy = 2x-3 O y = -7x +6 O y = -2x O y = -6x + 5

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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An equation of the line tangent to the graph of f (x)= x(1–2x)' at the point (1,–1) is O y = 7x -8 O y = 2x -3 O y = -7x +6 O y = -2x y = -6x + 5 Aa étv MacBook Air DII S0 F10 F7 FB F6 F3 & 5 6 7 8 9 3 4 P W R т Y
Transcribed Image Text:An equation of the line tangent to the graph of f (x)= x(1–2x)' at the point (1,–1) is O y = 7x -8 O y = 2x -3 O y = -7x +6 O y = -2x y = -6x + 5 Aa étv MacBook Air DII S0 F10 F7 FB F6 F3 & 5 6 7 8 9 3 4 P W R т Y
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