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Direction: Find the derivative of the function. g(z) = (3 – 2") (zª - z + 1) Select one: g'(x) = -bxª + 12r² – 2x – 3 O g'(x) = -5xª – 12x² + 2x – 3 O g'(r) = 5zª + 127² 2x + 3 O g'(z) = 5z4 + 127 + 2x – 3

Direction: Find the derivative of the function. g(z) = (3 – 2") (zª - z + 1) Select one: g'(x) = -bxª + 12r² – 2x – 3 O g'(x) = -5xª – 12x² + 2x – 3 O g'(r) = 5zª + 127² 2x + 3 O g'(z) = 5z4 + 127 + 2x – 3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Direction: Find the derivative of the function. g(z) = (3 – 2') (z² – z + 1) Select one: O g'(z) = -5zʻ + 12x² – 2r – 3 O g'(z) = -5xª 12x? + 2x – 3 O g'(x) = 5z" + 12r² 2x +3 O g'(z) = 5z4 + 12z + 2x – 3 Clear my choice
Transcribed Image Text:Direction: Find the derivative of the function. g(z) = (3 – 2') (z² – z + 1) Select one: O g'(z) = -5zʻ + 12x² – 2r – 3 O g'(z) = -5xª 12x? + 2x – 3 O g'(x) = 5z" + 12r² 2x +3 O g'(z) = 5z4 + 12z + 2x – 3 Clear my choice
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