We have created a 95% confidence interval for μ with the result (148, 196). What conclusion will we make if we test H0: μ = 190 vs. Ha:μ ≠ 190 at α = 5%? A. Reject the alternative hypothesis B. Reject the null hypothesis C. Fail to reject the null hypothesis D. Type I error

We have created a 95% confidence interval for μ with the result (148, 196). What conclusion will we make if we test H0: μ = 190 vs. Ha:μ ≠ 190 at α = 5%? A. Reject the alternative hypothesis B. Reject the null hypothesis C. Fail to reject the null hypothesis D. Type I error

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.1: Measures Of Center

Problem 9PPS

See similar textbooks

Similar questions

n=10 b = 0.50 sb = 0.02 α=0.05 find the confidence interval for β.
We have created a 95% confidence interval for μ with the result (10, 15). What decision will we make if we test H0: μ =16 versus H1: μ ≠ 16 at a = 0.10? Select one: a. Reject H0 in favor of H1. b. We cannot tell what our decision will be from the information given. c. Fail to reject H0 in favor of H1. d. Accept H0 in favor of H1.
Construct a 99 % confidence interval for the difference between the mean lifetimes of two kinds of light bulbs, given that a random sample of 40 light bulbs of the first kind lasted on the average 41 hours of continuous use and 50 light bulbs of the second kind lasted on the average 40. hours of continuous. use. The population standard deviations are known to be o1 = 26 and o2 = 22. Solution For a = 0.06, we find from Table III that z0.03 = 94% confidence interval for µi – 1.88. Therefore, the uz is 262 (418 - 402) – 1.88 · V 40. 222 < H1 - 42 50 262 222 + 40 < (418 – 402) +1.88 · 50
A 95% confidence interval for u was given as -5.65 < u < 2.61. What would a test for Ho : µ = 0 vs H1 : µ # 0 conclude? A. reject the null hypothesis at a = 0.05 and all smaller a B. fail to reject the null hypothesis at a = = 0.05 and all smaller a C. reject the null hypothesis at a = 0.05 and all larger a D. fail to reject the null hypothesis at a = - 0.05 and all larger
Bob selects independent random samples from wo populations and obtains the values p1 0.700 and p2 = 0.500. He constructs the 95% confidence interval for p1 – P2 and gets: 0.200 + 1.96(0.048) = 0.200 ± 0.094. Note that 0.048 is called the estimated standard error of p1 – p2 (the ESE of the estimate). Tom wants to estimate the mean of the success ates: Pi + P2 2 (a) Calculate Tom's point estimate. (b) Given that the estimated standard er- ror of (pi + P2)/2 is 0.024, calculate the 95% confidence interval estimate of (pi + P2)/2. Hint: The answer has our usual form: Pt. est. ±1.96 × ESE of the estimate. Carl selects one random sample from a popu- ation and calculates three confidence intervals for p. His intervals are below. A C p+0.080 p±0.040 p± 0.072 Match each confidence interval to its level, with evels chosen from: 80%, 90%, 95%, 98%, and 99%. Note: Clearly, two of these levels will not be used. You do not need to explain your reasoning
On a certain hearing ability test, the mean is 300 and the standard deviation is 20. Thebetter you can hear, the higher your score. Can people who clean their ears frequentlyhear better than others? You take a sample of 31 people who clean their earsfrequently. Their sample mean test score is 308. Do a hypothesis test with α = 0.01.H 0 : People who clean their ears regularly hear at the same level that everyone elsedoes: µ = 300. c. Calculate your test statistic and draw it on your null hypothesis curve. This is justyour sample statistic ( or ) converted to a Z-score on your null hypothesis samplingdistribution. Make sure you are using the appropriate SE formula! Use forproportions and for means. d. Treat your test statistic as a Z-score and look up the area beyond it in the Z-table.That is your p-value. It may be helpful to shade this on your curve. (Remember, ifyou have a < in your alternative hypothesis, you’re looking at the area below yourtest statistic. If you have a…
Please answer this question for me because i do not understand how to work it.
Find the critical values for each. z α/2 for the 95% confidence interval z α/2 for the 99% confidence interval z α/2 for the 90% confidence interval z α/2 for the 92.5% confidence interval
Find the 95% confidence interval for μ given that n = 16, X̄ = 28 and σ = 6.
Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…
Only about 16% of all people can wiggle their ears. Is this percent lower for millionaires? Of the 357 millionaires surveyed, 50 could wiggle their ears. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≥ = ≠ ≤ (please enter a decimal) H1:H1: ? p μ Select an answer ≠ = > < (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly lower than 16% at αα = 0.01, so there is statistically significant evidence to conclude that the population…
The data for a random sample of six paired observations are shown in the table. a. Calculatex and s b. Express μ in terms of μ, and μ₂- c. Form a 90% confidence interval for Hd. d. Test the null hypothesis Ho: H = 0 against the alternative hypothesis H₂: #0. Use α=0.10. a. Calculate the difference between each pair of observations by subtracting observation from observation 1. Find X- (Round to two decimal places as needed.) (-) Pair 1 2 5 6 Population 1 Sample (Observation 1) 5 12 11 6 3 3 Population 2 Sample (Observation 2) 3 Q