We have a random variable X, withE(X) = {5, 2, 10), Px (5) = 1/3.Px (2) = 1/6 et Px (10) = 1/2. We search: (1) Ex [5+ 2+ 10]. (ii) The average value ofX: x = Ex[x]. (iii) The average power of X:Ex[x²]. (iv) The variance of Y: 2 Fullr Eur²1 2

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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We have a random variableX, withE(X) = {5,2, 10}, Px (5) = 1/3,Px(2) = 1/6 et Px(10) = 1/2. We search :
(i) Ex[5 + 2 + 10].
(ii) The average value of X : µx = Ex[x].
(iii) The average power of X:Ex[x²].
(iv) The variance of X :o = Ex[(x – ux)²] = Ex[x²] – µz.
%3D
Transcribed Image Text:We have a random variableX, withE(X) = {5,2, 10}, Px (5) = 1/3,Px(2) = 1/6 et Px(10) = 1/2. We search : (i) Ex[5 + 2 + 10]. (ii) The average value of X : µx = Ex[x]. (iii) The average power of X:Ex[x²]. (iv) The variance of X :o = Ex[(x – ux)²] = Ex[x²] – µz. %3D
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