We define the function foo on natural numbers as follows: foo(n) = n, if 0 < n < 10 (i.e. n > 0 and n < 10) • foo(n) = 1+2 · foo(n – 10), if n > 10 (where “"." is the product function) Write a Python function: def fooDPBU (n) that, on input n, returns foo(n). Your function should use dynamic programming

We define the function foo on natural numbers as follows: foo(n) = n, if 0 < n < 10 (i.e. n > 0 and n < 10) • foo(n) = 1+2 · foo(n – 10), if n > 10 (where “"." is the product function) Write a Python function: def fooDPBU (n) that, on input n, returns foo(n). Your function should use dynamic programming

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

In this python program, explain every line of this code. Thank you. Source code: # Function def f(x): return 1/(x*(1 + x**3)) # Trapezoidal Rule implementationdef trapezoidal(u,l,n,dx): sumv = f(u) + f(l) for i in range(n): t = l + i*dx sumv += 2*f(t) sumv *= dx/2 return sumv # Input datal = float(input("Lower limit : "))u = float(input("Upper limit : "))n = int(input("Number of iterations : "))dx = 0.05print("Result ",trapezoidal(u,l,n,dx))
Write a function(define) the_divisor(n, bound), that takes in two int values. N is the number you search for a divisor and bound will also be an integer. The function the_divisor should return the smallest divisor which is greater than bound. If no such integers exists, return -1. You cannot assume that the first argument will be larger than the second. In python >>> the_divisor(25,3) 5 >>>the_divisor(5,25) -1
only atom code 1. Explain the problem with the following program: void f(int x, int y) { if(x==1) { cout << y << "\n"; return; } cout << y << "\n"; f(x, y+=2);} int main() { f(3, 2); return 0;} 2. Fix the function by rewriting any incorrect code.3. Identify the parts of a recursive function.4. Diagram the runtime stack of the corrected program when it is at its most complex. Mark the top and bottom of the stack for clarity.
Write a function count_evens() that has four integer parameters, and returns the count of parameters where the value is an even number (i.e. evenly divisible by 2). Ex: If the four parameters are: 1 22 11 40 then the returned count will be: 2 Hint: Use the modulo operator % to determine if each number is even or odd. Your program must define the function:count_evens(num1, num2, num3, num4) python # Define your function here if __name__ == '__main__': num1 = int(input()) num2 = int(input()) num3 = int(input()) num4 = int(input()) result = count_evens(num1, num2, num3, num4) print('Total evens:', result)
(1) Consider the following pseudocode of a function which takes an integer n ≥ 0 as input. Function foo(n) if n=0 then | Return; end for i=0 to n - 1 do Print "*¹; end foo(n-1); Let T(n) be the number of times the above function prints a star (*) when called with input n ≥ 0. What is T(n) exactly, in terms of only n (and not values like T(n-1) or T(n-2))? Prove your statement.
Implement a function rollsToRepeat in Python that simulates a dice game in which a pair of dice are rolled repeatedly until some total on the dice occurs the specified number of times. Details: accepts one integer argument, n , the number of repeats required before the game ends rolls a pair of dice repeatedly until some dice total has repeated n times returns the total number of times the pair of dice was rolled For example, using a random seed of 85 , the sequence of rolled pairs will be : (2, 6), (5, 1),(3, 2), (2, 4), (3, 5), (2, 6), (4, 5), (5, 2), (6, 5), (5, 5), ... If you runrollsToRepeat with n=1 , only 1 repeat is required. On the first roll, the total 8=2+6 is repeated once (as wouldany first roll). So the simulation stops and the function returns 1. This always happens whenn=1 . n=2 , some total must repeat twice. This first occurs on the 4throll, when the total of 6occurs for the 2ndtime. n=3 , some total must repeat three times. This first occurs on the 6throll, when…
Remember that an integer n is prime if (i) n> 2 and (ii) it is only divisible by 1 and n itself. Subtask I: You will start by implementing a function is_prime(n: int) -> bool that returns True if the number n is prime and False otherwise. For example: • is_prime(1) should return False. is_prime(2) should return True. is_prime(-2) should return False. is_prime(5) should return True. • is_prime(41) should return True. • is_prime(323) should return False. Subtask II: The thing is, many people believe prime numbers bring sadness and must be avoided. To this end, you'll write a function sans_primes(numbers: list[int]) -> list[int] that takes in a list of integers and returns the numbers in the input list in the original order, except that every prime number is banned, so it will be excluded and numbers that come immediately after a prime number will also be excluded. For example: • sans_primes([1, 4, 9, 10]) should return [1, 4, 9, 10]. • sans_primes([1, 11, 9, 10, 17]) should return [1,…
Define a function in Python that takes a positive integer n as a parameter and prints all numbers in the range 1 to n having the last digit equal to 5.
Program in python There is function F. Give an integer n (n ≥ 2), consider the prime factorization n=pi³1 P2²₂ Let g = ged(ky, k₂. k) and m, = k/g The function F is defined as F(n) = P11 P2" Prr Now, we have to summing up the value of this function for the first N natural numbers, we have w to evaluate the following expression for a given value of N: F(2) + F(3)+...+F(N) As the above sum can be extremely large Example if F(125)=5, thus the answer for this is by five more than for the previous one.
In C++, m%n is the remainder when the integer m is divided by the integer n. We can define a function to test whether an integer is even as follows: bool even(int k) { if ( k % 2 == 1 ) return false; else return true;} Translate this function into a standard mathematical function specification.
Use python
write this in c++ format function sequence(n){ var n = 10; // this is just for explanation you can take any value from user input var arr = [n]; //this is to store result //Continue to generate numbers in this way until N becomes equal to 1 while(n > 1){ //check if even if(n % 2 == 0){ //If N is an even number, then divide N by two to get a new value for N n = n / 2; } else{ //If N is an odd number, then multiply N by 3 and add 1 to get a new value for N. n = (n * 3) + 1; } arr.push(n); } Logger.log("sequesnce: "+ arr) Logger.log("Number of terms: "+arr.length);}