We could implement the Sieve of Eratosthenes using a while () loop: Eratosthenes <- function (n) { # Print prime numbers up to n (based on the sieve of Eratosthenes) if (n >= 2) { sieve <- seq (2, n) primes <-c() while (length (sieve) > 0) { p <- sieve [1] primes < c (primes, p) sieve <- sieve [ (sieve %% p) != 0] } } } return (primes) else { stop ("Input value of n should be at least 2.") Modify this function using break to take advantage of the above recult

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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use R prorgamming

We could implement the Sieve of Eratosthenes using a while () loop:
Eratosthenes <- function (n) {
# Print prime numbers up to n (based on the sieve of Eratosthenes)
if (n = 2) {
}
sieve <- seq (2, n)
primes <- c()
while (length (sieve) > 0) {
p < sieve [1]
primes < c (primes, p)
sieve <- sieve [ (sieve %% p) != 0]
}
return (primes)
} else {
stop ("Input value of n should be at least 2.")
Modify this function using break to take advantage of the above
result
Transcribed Image Text:We could implement the Sieve of Eratosthenes using a while () loop: Eratosthenes <- function (n) { # Print prime numbers up to n (based on the sieve of Eratosthenes) if (n = 2) { } sieve <- seq (2, n) primes <- c() while (length (sieve) > 0) { p < sieve [1] primes < c (primes, p) sieve <- sieve [ (sieve %% p) != 0] } return (primes) } else { stop ("Input value of n should be at least 2.") Modify this function using break to take advantage of the above result
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