We are standing on the top of a 48 foot tall building and launch a small object upward. The object's vertical altitude, measured in feet, after t seconds is h(t) -16t2 +32t+48. What is the highest altitude that the object reaches? =- feet
We are standing on the top of a 48 foot tall building and launch a small object upward. The object's vertical altitude, measured in feet, after t seconds is h(t) -16t2 +32t+48. What is the highest altitude that the object reaches? =- feet
Chapter9: Quadratic Equations And Functions
Section9.5: Solve Applications Of Quadratic Equations
Problem 9.78TI: A man throws a ball into the air with a velocity of 96 ft/s. Use the formula h=16t2+v0t to determine...
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![We are standing on the top of a 48 foot tall building and launch a small object upward. The object's
vertical altitude, measured in feet, after t seconds is h(t)= -16t2 + 32t+48. What is the highest
altitude that the object reaches?
feet](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff473cd06-09b6-4988-90fd-a0a49a37024f%2F92e6484f-d7c3-4e5f-88a0-fb652f291be4%2Friuls38_processed.jpeg&w=3840&q=75)
Transcribed Image Text:We are standing on the top of a 48 foot tall building and launch a small object upward. The object's
vertical altitude, measured in feet, after t seconds is h(t)= -16t2 + 32t+48. What is the highest
altitude that the object reaches?
feet
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