We are interested in conducting the following hypothesis test at a = 0.05. Ho: o2 > 100 Hạ: o? < 100 A random sample of 30 data points showed s? = 125. Determine the critical value. Keep 3 decimals.
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- 4h. Consider the following hypothesis test. H0: ?1 − ?2 = 0 Ha: ?1 − ?2 ≠ 0 The following results are from independent samples taken from two populations. Sample 1 Sample 2 n1 = 35 n2 = 40 x1 = 13.6 x2 = 10.1 s1 = 5.6 s2 = 8.1 (b) What is the degrees of freedom for the t distribution? (Round your answer down to the nearest integer.) (c) What is the p-value? (Round your answer to four decimal places.) p-value =Do the results of part F agree with Chebychev's Theorem? Explain. You can type your answer with equations/formulas for this question.The one-sample ?t‑statistic for a test of ?0:?=42H0:μ=42 versus ?1:?<42H1:μ<42 based on ?=15n=15 observations has the value ?=−0.867t=−0.867, where ?0H0 and ?1H1are the null and alternative hypotheses, respectively. The sample size is denoted by ?n. Use this ?t‑table to determine which two ?-valuesP-values bracket the ?-valueP-value of the test. Report your answers in decimal form as listed in the ?t‑table.
- pleaseee sir solve question 18 and 19Molly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value? If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…Next question A golf association requires that golf balls have a diameter that is 1.68 inches. To deter hform to the standard, a random sample of golf balls was selected. Their diameters are shown in the accompanying data table. Do the golf balls conform to the standards? Use the x = 0.01 level of significance. Click the icon to view the data table. First determine the appropriate hypotheses. Ho: H₁: (Type integers or decimals. Do not round.) Find the test statistic. (Round to two decimal places as needed.) Find the P-value. (Round to three decimal places as needed.) What can be concluded from the hypothesis test? O A. Reject Ho. There is sufficient evidence to conclude that the golf balls do not conform to the association's standards at the α = 0.01 level of significance. B. Do not reject Ho. There is not sufficient evidence to conclude that the golf balls do not conform to the association's standards at the x = 0.01 level of significance. C. Do not reject Ho. There is sufficient…
- a. Compute the p-value for the test (use R). Round to the nearest 3rd decimal place, 0.xxx. b. Make and justify a statistical decision at the α= 0.15 significance level and state your conclu-sions in context of the problem.Which of the following is the best decision and conclusion based on the result below? H.: p = 0.10 Ha:p + 0.10 Critical Value: +1.645 Computed Test Statistics: z = 5.61 O a. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O b. Since the computed test statistics is less than the critical value, do not reject Ho. Therefore, we conclude that at 0.10evel of significance, there is enough evidence that the population proportion is different from 10%. O c. Since the computed test statistics is greater than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there is enough evidence that the population proportion is different from 10%. O d. Since the computed test statistics is less than the critical value, reject Ho. Therefore, we conclude that at 0.10 level of significance, there…. A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ, of the population from which the sample was drawn. Use the critical-value approach. Sample mean = 3.12 s = 0.59 n = 9 α = 0.01 H0: µ = 2.85 H1: µ > 2.85 The test statistics is (Round to three decimal places)
- 7. In testing the hypothesis The test statistic is found to be Z = 2.03. Which of the following is the correct p-value? Họ: u = 35 Hạ: u > 35 %3D A. 0.9788 B. 0.0424 C. 0.0212 D. 1.9576 E. None of theseUsing the first image's question, answer all the questions asked in second image.:11 PM Tue Dec 14 ohm.lumenlearning.com Test the claim that the mean GPA of night students is larger than 3.3 at the 0.10 significance level. The null and alternative hypothesis would be: Ho:u > 3.3 Ho:p= 0.825 Họ:p 0.825 Ho:µ = 3.3 Ho:µ 0.825 H1:p 3.3 The test is: left-tailed right-tailed two-tailed o Based on a sample of 80 people, the sample mean GPA was 3.31 with a standard deviation of 0.04 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis Reject the null hypothesis Question Help: DPost to forum Submit Question