Water is flowing in a trapezoidal channel at a rate of Q = 20 m³/s. The critical depth y for such a channel must satisfy the equation: 1 -3 B = 0 where g = 9.81 m/s?, Ac =the cross-sectional area (m?), and B = Q? the width of the channel at the surface (m). For this case, the width and the cross-sectional area can be related to depth y by B = 3 + y and A. = 3y +: Solve for the critical depth using bisection method using the initial guesses x = 0.5 and xu = 2.5.

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Water is flowing in a trapezoidal channel at a rate of Q = 20 m³/s. The critical depth y for such a channel
must satisfy the equation: 1 -3 B = 0 where g = 9.81 m/s?, Ac =the cross-sectional area (m?), and B =
Q?
the width of the channel at the surface (m). For this case, the width and the cross-sectional area can be
related to depth y by B = 3 + y and A. = 3y +:
Solve for the critical depth using bisection method using
the initial guesses x = 0.5 and xu
= 2.5.
Transcribed Image Text:Water is flowing in a trapezoidal channel at a rate of Q = 20 m³/s. The critical depth y for such a channel must satisfy the equation: 1 -3 B = 0 where g = 9.81 m/s?, Ac =the cross-sectional area (m?), and B = Q? the width of the channel at the surface (m). For this case, the width and the cross-sectional area can be related to depth y by B = 3 + y and A. = 3y +: Solve for the critical depth using bisection method using the initial guesses x = 0.5 and xu = 2.5.
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