Water is flowing in a 90ο pipe with uniform cross section area of A=0.0083 m2. The velocity along the horizontal direction is v1=6.0 m/s. The pressure at the section 1 is p1=500kPa. Elevation difference and energy losses can be neglected. The density of water is ρ=1000kg/m3. An external force is needed to hold the pipe in equilibrium.(1) Select the correct expression of the external force component in the horizontal direction Rx_________ A. B. C. D. Water is flowing in a 90° pipe with uniform cross section area of A=0.0083 m². Thevelocity along the horizontal direction is v1=6.0 m/s. The pressure at the section 1 isP1=500kPa. Elevation difference and energy losses can be neglected. The density of wateris p=1000kg/m³. An external force is needed to hold the pipe in equilibrium.(1) Select the correct expression of the external force component in the horizontal directionRx49.₁ V₁P₁A+yOAR =- PON 1XOB.R_=PQ¹1x+XP₂ A₂OCR_=P₂₁A₁+POVLEOD-R =-P₁A₁-PON IX

Force in X-direction P1A1-Rx =m(Vf - Vi ) P1A1 - Rx = pQ(0 - V1 ) Rx = P1 A1 + pQV1 p= density of…

Answered: Water is flowing in a 90° pipe with…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Water is flowing in a 90^ο pipe with uniform cross section area of A=0.0083 m². The velocity along the horizontal direction is v_{1=6.0 m/s}. The pressure at the section 1 is p_1=500kPa. Elevation difference and energy losses can be neglected. The density of water is ρ=1000kg/m³. An external force is needed to hold the pipe in equilibrium.

(1) Select the correct expression of the external force component in the horizontal direction R_x_________

A.

B.

C.

D.

Water is flowing in a 90° pipe with uniform cross section area of A=0.0083 m². The
velocity along the horizontal direction is v1=6.0 m/s. The pressure at the section 1 is
P1=500kPa. Elevation difference and energy losses can be neglected. The density of water
is p=1000kg/m³. An external force is needed to hold the pipe in equilibrium.
(1) Select the correct expression of the external force component in the horizontal direction
Rx
49.₁ V₁
P₁A
+y
OAR =- PON 1X
OB.R_=PQ¹1x
+X
P₂ A₂
OCR_=P₂₁A₁+POVLE
OD-R =-P₁A₁-PON IX

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