Watch help video Solve for x. 21

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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**Secant/Tangent Intersection Outside Circle**

**Date:** Jun 18, 2:12:52 AM

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**Watch help video**

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**Solve for \(x\).**

*Explanation of Diagram:*

1. The diagram features a circle with a secant and a tangent line intersecting outside of the circle.
2. The secant line extends from an exterior point, passing through the circle, creating two segments. One segment outside the circle is labeled as \(x\), and the external segment is labeled as 4.
3. The product of the lengths of the whole secant segment (21 + 4) and its external segment (4) is equal to the product of the lengths of the tangent segment (\(x\)) squared.

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\( Answer: \) [Input box for answer] \( Submit Answer \) Button.

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*Note:* To solve for \(x\), use the secant-tangent theorem, stated as \( (\text{whole secant segment} \times \text{external secant segment} = (\text{tangent segment})^2) \). 

Therefore, \( (21+4) \times 4 = x^2 \).

Solving this will give you the value of \(x\).
Transcribed Image Text:**Secant/Tangent Intersection Outside Circle** **Date:** Jun 18, 2:12:52 AM --- **Watch help video** --- **Solve for \(x\).** *Explanation of Diagram:* 1. The diagram features a circle with a secant and a tangent line intersecting outside of the circle. 2. The secant line extends from an exterior point, passing through the circle, creating two segments. One segment outside the circle is labeled as \(x\), and the external segment is labeled as 4. 3. The product of the lengths of the whole secant segment (21 + 4) and its external segment (4) is equal to the product of the lengths of the tangent segment (\(x\)) squared. --- \( Answer: \) [Input box for answer] \( Submit Answer \) Button. --- *Note:* To solve for \(x\), use the secant-tangent theorem, stated as \( (\text{whole secant segment} \times \text{external secant segment} = (\text{tangent segment})^2) \). Therefore, \( (21+4) \times 4 = x^2 \). Solving this will give you the value of \(x\).
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