Part A: This table gives the number of children and adults in a studywho did and who did not have an adverse reaction to a new vaccine.ChildrenAdultsTotalAdverse383371reactionNo adverse468217685reactionTotal506250756 Was the absolute risk of an adverse reaction greater for children orfor adults? Choose the best answer.agreater for adults because 33/250 > 38/506bgreater for children because 38/71 > 33/71greater for adults because (38 – 33)/(506 – 250) < 1dgreater for children because more children had adverse reactions,38 > 33The absolute risk was about the same because 38 and 33 aren'tevery different

We have to check if risk is more for children than adults or not.

Answered: Was the absolute risk of an adverse…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(Q2) A store room measured in length equal to (5m + 3 cm), measured width equal to (4m 2cm) measured height equal to (3m + 4 cm), find the total volume of this room and the standard deviation.
Apparently what I put was incorrect.
a1
(10) When estimating the difference between 2 proportions, show that when n₁ = n₂ = n, we can be at least 100(1 - a)% confident that the error that we make when using P1 P2 as an estimate of p₁ - P2 is less than e when n = a/2 2€²
Glaucoma is a leading cause of blindness in the United States, N. Ehlers measured the difference in corneal thickness (in microns) between the two eyes of eight patients. Each patient had one eye that had glaucoma and one eye that was normal. The difference was measured as the corneal thickness of normal eye – corneal thickness of eye with Glaucoma. Corneal thickness is important because it can mask an accurate reading of eye pressure. Use ? = .05. Hypothesis: H0: μd=0Ha: μd≠0 Using output Test statistics : t=0.134P value=0.897 Degrees of freedom (df): df=7 Level of significance: α=0.05 Decision: P value > 0.05 thus we fails to reject null hypothesis. Question a)Write a report summarizing your findings. When writing the report consider that medical staff estimate that a difference of 4.5 microns or more could impact on their ability to interpret eye pressure correctly. b) Define for the hypothesis stated in part b) what a type 1 error and type 2 error would mean. Is it possible…
Q1: A FSHN student was trying to see if onion cut in water produces significantly less tears compared to onion cut in the air. She did an experiment on 6 onions. She cut onions into half, one half was chopped in water & the other half was chopped in the air. Here is the amount of tears (in ml) she collected: air: 3.2 2.3 2.6 2.8 3.0 3.7 water: 0.2 0.03 0.09 0.1 0.01 0.15 a) What kind of test would you use to analyze this data? and Why? T test unequal variance, because there is different between variance b) Do you think the onion chopped in the air produce significantly more tears than onion cut in water? Give two reasons from the analysis to support your answer.
How to Compute t and p for the difference between means?
The given population is 3476, n = 528, what will be the value of e (margin of error)? Show clear solutions
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.A random sample of 5280 permanent dwellings on an entire reservation showed that 1620 were traditional hogans.
A researcher reports an F-ratio with df = 3, 36 from an independent-measures research study. Based on the df values, how many treatments were compared in the study and what was the total number of subjects participating in the study? O 4 treatments and 40 subjects O 2treatments and 35 subjects O 3 treatments and 37 subjects O 4 treatments and 36 subjects
A medical researcher tested a new treatment for poison ivy against the traditional ointment. He concluded that the new treatment is more effective. Explain what the P-value of 0.037 means in this context. Explain what the P-value of 0.037 means in this context. O A. There is a 3.7% difference between the effectiveness of the new treatment and the effectiveness of the traditional ointment. O B. If there is no difference in effectiveness, the chance of seeing an observed difference this large or larger is 3.7% by natural sampling variation. O C. If there is a difference in effectiveness, the chance of seeing an observed difference this large or larger is 3.7% by natural sampling variation. D. There is a 3.7% chance that the new treatment is effective.

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