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W=0 31. Suppose the sled in Exercise 6.30 is initially at rest at x = 0. Use the work-energy theorem to find the speed of the sle at a) x = 8.0 m; b) x = 12.0 m. uk-mv² 2F=mu F 1_E₂ 上 k = 1 / / ²01² k = 15v² 20

W=0 31. Suppose the sled in Exercise 6.30 is initially at rest at x = 0. Use the work-energy theorem to find the speed of the sle at a) x = 8.0 m; b) x = 12.0 m. uk-mv² 2F=mu F 1_E₂ 上 k = 1 / / ²01² k = 15v² 20

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Solve 31 For 31, assume the sled is the crate in 4 Number 4 is only there to provide context for 31, number 4 is not the question I am asking to be solved Thanks!
4. A factory worker pushes a 30.0-kg crate a distance of 4.5 m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and floor is 0.25. a) What magnitude of force mus the worker apply? b) How much work is done on the crate by this force? c) How much work is done on the crate by friction? d) How much work is done by the normal force? By gravity? e) What is the total work done on the crate? F a: U w= F·d a. 757.57 h. 337.5J 07- ST In Oles F IF G F
Transcribed Image Text:4. A factory worker pushes a 30.0-kg crate a distance of 4.5 m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and floor is 0.25. a) What magnitude of force mus the worker apply? b) How much work is done on the crate by this force? c) How much work is done on the crate by friction? d) How much work is done by the normal force? By gravity? e) What is the total work done on the crate? F a: U w= F·d a. 757.57 h. 337.5J 07- ST In Oles F IF G F
F=75N w=0 31. Suppose the sled in Exercise 6.30 is initially at rest at x = 0. Use the work-energy theorem to find the speed of the sle at a) x = 8.0 m; b) x = 12.0 m. uk-mv² MF₂ F 2F=ma k= = ² ²00² k=150²
Transcribed Image Text:F=75N w=0 31. Suppose the sled in Exercise 6.30 is initially at rest at x = 0. Use the work-energy theorem to find the speed of the sle at a) x = 8.0 m; b) x = 12.0 m. uk-mv² MF₂ F 2F=ma k= = ² ²00² k=150²
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